(5x^2+5x-7)(2x-1)=0

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Solution for (5x^2+5x-7)(2x-1)=0 equation: 


Simplifying
(5x2 + 5x + -7)(2x + -1) = 0

Reorder the terms:
(-7 + 5x + 5x2)(2x + -1) = 0

Reorder the terms:
(-7 + 5x + 5x2)(-1 + 2x) = 0

Multiply (-7 + 5x + 5x2) * (-1 + 2x)
(-7(-1 + 2x) + 5x * (-1 + 2x) + 5x2 * (-1 + 2x)) = 0
((-1 * -7 + 2x * -7) + 5x * (-1 + 2x) + 5x2 * (-1 + 2x)) = 0
((7 + -14x) + 5x * (-1 + 2x) + 5x2 * (-1 + 2x)) = 0
(7 + -14x + (-1 * 5x + 2x * 5x) + 5x2 * (-1 + 2x)) = 0
(7 + -14x + (-5x + 10x2) + 5x2 * (-1 + 2x)) = 0
(7 + -14x + -5x + 10x2 + (-1 * 5x2 + 2x * 5x2)) = 0
(7 + -14x + -5x + 10x2 + (-5x2 + 10x3)) = 0

Combine like terms: -14x + -5x = -19x
(7 + -19x + 10x2 + -5x2 + 10x3) = 0

Combine like terms: 10x2 + -5x2 = 5x2
(7 + -19x + 5x2 + 10x3) = 0

Solving
7 + -19x + 5x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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